Negative exponent derivative problems use the same power rule as positive exponent problems. The main idea is to bring the exponent down in front, then subtract one from the exponent. When a variable expression is written in the denominator, it can be rewritten with a negative exponent before taking the derivative.
Find the derivative of each function.
\(\textbf{1)}\) \(f(x)=x^{-5}\)
The answer is \(f'(x)=-5x^{-6}\)
\(\,\,\,\,\,f(x)=x^{-5}\)
\(\,\,\,\,\,f'(x)=-5x^{-5-1}\)
\(\,\,\,\,\,f'(x)=-5x^{-6}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-5x^{-6}\)
\(\textbf{2)}\) \(f(x)=-x^{-4}\)
The answer is \(f'(x)=4x^{-5}\)
\(\,\,\,\,\,f(x)=-x^{-4}\)
\(\,\,\,\,\,f'(x)=-(-4)x^{-4-1}\)
\(\,\,\,\,\,f'(x)=4x^{-5}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=4x^{-5}\)
\(\textbf{3)}\) \(f(x)=x^{-1}\)
The answer is \(f'(x)=-x^{-2}\)
\(\,\,\,\,\,f(x)=x^{-1}\)
\(\,\,\,\,\,f'(x)=-1x^{-1-1}\)
\(\,\,\,\,\,f'(x)=-x^{-2}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-x^{-2}\)
\(\textbf{4)}\) \(f(x)=\displaystyle\frac{1}{x^{5}}\)
The answer is \(f'(x)=-5x^{-6}\)
\(\,\,\,\,\,f(x)=\displaystyle\frac{1}{x^5}\)
\(\,\,\,\,\,f(x)=x^{-5}\)
\(\,\,\,\,\,f'(x)=-5x^{-6}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-5x^{-6}\)
\(\textbf{5)}\) \(f(x)=-\displaystyle\frac{1}{x^{4}}\)
The answer is \(f'(x)=4x^{-5}\)
\(\,\,\,\,\,f(x)=-\displaystyle\frac{1}{x^4}\)
\(\,\,\,\,\,f(x)=-x^{-4}\)
\(\,\,\,\,\,f'(x)=-(-4)x^{-5}\)
\(\,\,\,\,\,f'(x)=4x^{-5}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=4x^{-5}\)
\(\textbf{6)}\) \(f(x)=\displaystyle\frac{1}{x}\)
The answer is \(f'(x)=-x^{-2}\)
\(\,\,\,\,\,f(x)=\displaystyle\frac{1}{x}\)
\(\,\,\,\,\,f(x)=x^{-1}\)
\(\,\,\,\,\,f'(x)=-1x^{-2}\)
\(\,\,\,\,\,f'(x)=-x^{-2}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-x^{-2}\)
\(\textbf{7)}\) \(f(x)=3x^{-2}\)
The answer is \(f'(x)=-6x^{-3}\)
\(\,\,\,\,\,f(x)=3x^{-2}\)
\(\,\,\,\,\,f'(x)=3(-2)x^{-2-1}\)
\(\,\,\,\,\,f'(x)=-6x^{-3}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-6x^{-3}\)
\(\textbf{8)}\) \(f(x)=-4x^{-3}\)
The answer is \(f'(x)=12x^{-4}\)
\(\,\,\,\,\,f(x)=-4x^{-3}\)
\(\,\,\,\,\,f'(x)=-4(-3)x^{-3-1}\)
\(\,\,\,\,\,f'(x)=12x^{-4}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=12x^{-4}\)
\(\textbf{9)}\) \(f(x)=\displaystyle\frac{7}{x^2}\)
The answer is \(f'(x)=-14x^{-3}\)
\(\,\,\,\,\,f(x)=\displaystyle\frac{7}{x^2}\)
\(\,\,\,\,\,f(x)=7x^{-2}\)
\(\,\,\,\,\,f'(x)=7(-2)x^{-3}\)
\(\,\,\,\,\,f'(x)=-14x^{-3}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-14x^{-3}\)
\(\textbf{10)}\) \(f(x)=-\displaystyle\frac{2}{x^6}\)
The answer is \(f'(x)=12x^{-7}\)
\(\,\,\,\,\,f(x)=-\displaystyle\frac{2}{x^6}\)
\(\,\,\,\,\,f(x)=-2x^{-6}\)
\(\,\,\,\,\,f'(x)=-2(-6)x^{-7}\)
\(\,\,\,\,\,f'(x)=12x^{-7}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=12x^{-7}\)
\(\textbf{11)}\) \(f(x)=5x^{-1}+2x^{-3}\)
The answer is \(f'(x)=-5x^{-2}-6x^{-4}\)
\(\,\,\,\,\,f(x)=5x^{-1}+2x^{-3}\)
\(\,\,\,\,\,f'(x)=5(-1)x^{-2}+2(-3)x^{-4}\)
\(\,\,\,\,\,f'(x)=-5x^{-2}-6x^{-4}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-5x^{-2}-6x^{-4}\)
\(\textbf{12)}\) \(f(x)=\displaystyle\frac{4}{x}+\frac{3}{x^2}\)
The answer is \(f'(x)=-4x^{-2}-6x^{-3}\)
\(\,\,\,\,\,f(x)=\displaystyle\frac{4}{x}+\frac{3}{x^2}\)
\(\,\,\,\,\,f(x)=4x^{-1}+3x^{-2}\)
\(\,\,\,\,\,f'(x)=4(-1)x^{-2}+3(-2)x^{-3}\)
\(\,\,\,\,\,f'(x)=-4x^{-2}-6x^{-3}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-4x^{-2}-6x^{-3}\)
\(\textbf{13)}\) \(f(x)=x^3+x^{-2}\)
The answer is \(f'(x)=3x^2-2x^{-3}\)
\(\,\,\,\,\,f(x)=x^3+x^{-2}\)
\(\,\,\,\,\,f'(x)=3x^2+(-2)x^{-3}\)
\(\,\,\,\,\,f'(x)=3x^2-2x^{-3}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=3x^2-2x^{-3}\)
\(\textbf{14)}\) \(f(x)=2x^4-6x^{-5}\)
The answer is \(f'(x)=8x^3+30x^{-6}\)
\(\,\,\,\,\,f(x)=2x^4-6x^{-5}\)
\(\,\,\,\,\,f'(x)=2(4x^3)-6(-5x^{-6})\)
\(\,\,\,\,\,f'(x)=8x^3+30x^{-6}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=8x^3+30x^{-6}\)
\(\textbf{15)}\) \(f(x)=\displaystyle\frac{x^2+1}{x}\)
The answer is \(f'(x)=1-x^{-2}\)
\(\,\,\,\,\,f(x)=\displaystyle\frac{x^2+1}{x}\)
\(\,\,\,\,\,f(x)=x+\frac{1}{x}\)
\(\,\,\,\,\,f(x)=x+x^{-1}\)
\(\,\,\,\,\,f'(x)=1-x^{-2}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=1-x^{-2}\)
\(\textbf{16)}\) \(f(x)=\displaystyle\frac{x^3-2}{x^2}\)
The answer is \(f'(x)=1+4x^{-3}\)
\(\,\,\,\,\,f(x)=\displaystyle\frac{x^3-2}{x^2}\)
\(\,\,\,\,\,f(x)=x-\frac{2}{x^2}\)
\(\,\,\,\,\,f(x)=x-2x^{-2}\)
\(\,\,\,\,\,f'(x)=1-2(-2)x^{-3}\)
\(\,\,\,\,\,f'(x)=1+4x^{-3}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=1+4x^{-3}\)
\(\textbf{17)}\) \(f(x)=\displaystyle\frac{3x^2-5}{x^3}\)
The answer is \(f'(x)=-3x^{-2}+15x^{-4}\)
\(\,\,\,\,\,f(x)=\displaystyle\frac{3x^2-5}{x^3}\)
\(\,\,\,\,\,f(x)=3x^{-1}-5x^{-3}\)
\(\,\,\,\,\,f'(x)=3(-1)x^{-2}-5(-3)x^{-4}\)
\(\,\,\,\,\,f'(x)=-3x^{-2}+15x^{-4}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-3x^{-2}+15x^{-4}\)
\(\textbf{18)}\) \(f(x)=\displaystyle\frac{2x^4+7}{x^5}\)
The answer is \(f'(x)=-2x^{-2}-35x^{-6}\)
\(\,\,\,\,\,f(x)=\displaystyle\frac{2x^4+7}{x^5}\)
\(\,\,\,\,\,f(x)=2x^{-1}+7x^{-5}\)
\(\,\,\,\,\,f'(x)=2(-1)x^{-2}+7(-5)x^{-6}\)
\(\,\,\,\,\,f'(x)=-2x^{-2}-35x^{-6}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-2x^{-2}-35x^{-6}\)
\(\textbf{19)}\) \(f(x)=\left(x^{-2}\right)^3\)
The answer is \(f'(x)=-6x^{-7}\)
\(\,\,\,\,\,f(x)=\left(x^{-2}\right)^3\)
\(\,\,\,\,\,f(x)=x^{-6}\)
\(\,\,\,\,\,f'(x)=-6x^{-7}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-6x^{-7}\)
\(\textbf{20)}\) \(f(x)=\displaystyle\frac{1}{x^2}+\frac{1}{x^5}\)
The answer is \(f'(x)=-2x^{-3}-5x^{-6}\)
\(\,\,\,\,\,f(x)=\displaystyle\frac{1}{x^2}+\frac{1}{x^5}\)
\(\,\,\,\,\,f(x)=x^{-2}+x^{-5}\)
\(\,\,\,\,\,f'(x)=-2x^{-3}-5x^{-6}\)
\(\,\,\,\,\,\)The answer is \(f'(x)=-2x^{-3}-5x^{-6}\)
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