Printable PDF and Answer Key 
Notes
It should be written PE(MD)(AS) instead of PEMDAS. Multiply and divide from left to right happen in the same step. Then add and subtract from left to right happens in the same step.
Practice Problems
\(\small{\textbf{1)}}\) \(2+5\times3\) The answer is \(17\)
\(\,\,\,\,\,\,2+5\times3\)
\(\,\,\,\,\,\,2+15\)
\(\,\,\,\,\,\,17\)
\(\,\,\,\,\,\,2+5\times3\)
\(\,\,\,\,\,\,2+15\)
\(\,\,\,\,\,\,17\)
\(\small{\textbf{2)}}\) \(8-6\div2\) The answer is \(5\)
\(\,\,\,\,\,\,8-6\div2\)
\(\,\,\,\,\,\,8-3\)
\(\,\,\,\,\,\,5\)
\(\,\,\,\,\,\,8-6\div2\)
\(\,\,\,\,\,\,8-3\)
\(\,\,\,\,\,\,5\)
\(\small{\textbf{3)}}\) \(3 \times 5-3\) The answer is \(12\)
\(\,\,\,\,\,\,3 \times 5-3\)
\(\,\,\,\,\,\,15-3\)
\(\,\,\,\,\,\,12\)
\(\,\,\,\,\,\,3 \times 5-3\)
\(\,\,\,\,\,\,15-3\)
\(\,\,\,\,\,\,12\)
\(\small{\textbf{4)}}\) \(3 \times (5-3)\) The answer is \(6\)
\(\,\,\,\,\,\,3 \times (5-3)\)
\(\,\,\,\,\,\,3 \times (2)\)
\(\,\,\,\,\,\,6\)
\(\,\,\,\,\,\,3 \times (5-3)\)
\(\,\,\,\,\,\,3 \times (2)\)
\(\,\,\,\,\,\,6\)
\(\small{\textbf{5)}}\) \(10-5\times2\) The answer is \(0\)
\(\,\,\,\,\,\,10-5\times2\)
\(\,\,\,\,\,\,10-10\)
\(\,\,\,\,\,\,0\)
\(\,\,\,\,\,\,10-5\times2\)
\(\,\,\,\,\,\,10-10\)
\(\,\,\,\,\,\,0\)
\(\small{\textbf{6)}}\) \(4+5\times3+2\) The answer is \(21\)
\(\,\,\,\,\,\,4+5\times3+2\)
\(\,\,\,\,\,\,4+15+2\)
\(\,\,\,\,\,\,19+2\)
\(\,\,\,\,\,\,21\)
\(\,\,\,\,\,\,4+5\times3+2\)
\(\,\,\,\,\,\,4+15+2\)
\(\,\,\,\,\,\,19+2\)
\(\,\,\,\,\,\,21\)
\(\small{\textbf{7)}}\) \(4^2-3 \times 2\) The answer is \(10\)
\(\,\,\,\,\,\,4^2-3 \times 2\)
\(\,\,\,\,\,\,16-3 \times 2\)
\(\,\,\,\,\,\,16-6\)
\(\,\,\,\,\,\,10\)
\(\,\,\,\,\,\,4^2-3 \times 2\)
\(\,\,\,\,\,\,16-3 \times 2\)
\(\,\,\,\,\,\,16-6\)
\(\,\,\,\,\,\,10\)
\(\small{\textbf{8)}}\) \(4 \times 6-1 \times2\) The answer is \(22\)
\(\,\,\,\,\,\,4 \times 6-1 \times2\)
\(\,\,\,\,\,\,24-1 \times2\)
\(\,\,\,\,\,\,24-2\)
\(\,\,\,\,\,\,22\)
\(\,\,\,\,\,\,4 \times 6-1 \times2\)
\(\,\,\,\,\,\,24-1 \times2\)
\(\,\,\,\,\,\,24-2\)
\(\,\,\,\,\,\,22\)
\(\small{\textbf{9)}}\) \(5-2+3\) The answer is \(6\)
\(\,\,\,\,\,\,5-2+3\)
\(\,\,\,\,\,\,3+3\)
\(\,\,\,\,\,\,6\)
\(\,\,\,\,\,\,5-2+3\)
\(\,\,\,\,\,\,3+3\)
\(\,\,\,\,\,\,6\)
\(\small{\textbf{10)}}\) \((3+5)^2-(4\div2)^2\) The answer is \(60\)
\(\,\,\,\,\,\,(3+5)^2-(4\div2)^2\)
\(\,\,\,\,\,\,(8)^2-(4\div2)^2\)
\(\,\,\,\,\,\,(8)^2-(2)^2\)
\(\,\,\,\,\,\,64-(2)^2\)
\(\,\,\,\,\,\,64-4\)
\(\,\,\,\,\,\,60\)
\(\,\,\,\,\,\,(3+5)^2-(4\div2)^2\)
\(\,\,\,\,\,\,(8)^2-(4\div2)^2\)
\(\,\,\,\,\,\,(8)^2-(2)^2\)
\(\,\,\,\,\,\,64-(2)^2\)
\(\,\,\,\,\,\,64-4\)
\(\,\,\,\,\,\,60\)
\(\small{\textbf{11)}}\) \(12-3\times4+1\) The answer is \(1\)
\(\,\,\,\,\,\,12-3\times4+1\)
\(\,\,\,\,\,\,12-12+1\)
\(\,\,\,\,\,\,0+1\)
\(\,\,\,\,\,\,1\)
\(\,\,\,\,\,\,12-3\times4+1\)
\(\,\,\,\,\,\,12-12+1\)
\(\,\,\,\,\,\,0+1\)
\(\,\,\,\,\,\,1\)
\(\small{\textbf{12)}}\) \(14\div7\times2\) The answer is \(4\)
\(\,\,\,\,\,\,14\div7\times2\)
\(\,\,\,\,\,\,2\times2\)
\(\,\,\,\,\,\,4\)
\(\,\,\,\,\,\,14\div7\times2\)
\(\,\,\,\,\,\,2\times2\)
\(\,\,\,\,\,\,4\)
\(\small{\textbf{13)}}\) \(14\div7-2\) The answer is \(0\)
\(\,\,\,\,\,\,14\div7-2\)
\(\,\,\,\,\,\,2-2\)
\(\,\,\,\,\,\,0\)
\(\,\,\,\,\,\,14\div7-2\)
\(\,\,\,\,\,\,2-2\)
\(\,\,\,\,\,\,0\)
\(\small{\textbf{14)}}\) \(16-4+8\) The answer is \(20\)
\(\,\,\,\,\,\,16-4+8\)
\(\,\,\,\,\,\,12+8\)
\(\,\,\,\,\,\,20\)
\(\,\,\,\,\,\,16-4+8\)
\(\,\,\,\,\,\,12+8\)
\(\,\,\,\,\,\,20\)
\(\small{\textbf{15)}}\) \(4+3\times2+6\div3\) The answer is \(12\)
\(\,\,\,\,\,\,4+3\times2+6\div3\)
\(\,\,\,\,\,\,4+6+6\div3\)
\(\,\,\,\,\,\,4+6+2\)
\(\,\,\,\,\,\,10+2\)
\(\,\,\,\,\,\,12\)
\(\,\,\,\,\,\,4+3\times2+6\div3\)
\(\,\,\,\,\,\,4+6+6\div3\)
\(\,\,\,\,\,\,4+6+2\)
\(\,\,\,\,\,\,10+2\)
\(\,\,\,\,\,\,12\)
\(\small{\textbf{16)}}\) \(10+2-3\times4\div2\) The answer is \(6\)
\(\,\,\,\,\,\,10+2-3\times4\div2\)
\(\,\,\,\,\,\,10+2-12\div2\)
\(\,\,\,\,\,\,10+2-6\)
\(\,\,\,\,\,\,12-6\)
\(\,\,\,\,\,\,6\)
\(\,\,\,\,\,\,10+2-3\times4\div2\)
\(\,\,\,\,\,\,10+2-12\div2\)
\(\,\,\,\,\,\,10+2-6\)
\(\,\,\,\,\,\,12-6\)
\(\,\,\,\,\,\,6\)
\(\small{\textbf{17)}}\) \((4+3)\times(4-2)^2\) The answer is \(28\)
\(\,\,\,\,\,\,(4+3)\times(4-2)^2\)
\(\,\,\,\,\,\,(7)\times(4-2)^2\)
\(\,\,\,\,\,\,(7)\times(2)^2\)
\(\,\,\,\,\,\,(7)\times4\)
\(\,\,\,\,\,\,28\)
\(\,\,\,\,\,\,(4+3)\times(4-2)^2\)
\(\,\,\,\,\,\,(7)\times(4-2)^2\)
\(\,\,\,\,\,\,(7)\times(2)^2\)
\(\,\,\,\,\,\,(7)\times4\)
\(\,\,\,\,\,\,28\)
\(\small{\textbf{18)}}\) \(8\times(5-2)^2-1\) The answer is \(71\)
\(\,\,\,\,\,\,8\times(5-2)^2-1\)
\(\,\,\,\,\,\,8\times(3)^2-1\)
\(\,\,\,\,\,\,8\times9-1\)
\(\,\,\,\,\,\,72-1\)
\(\,\,\,\,\,\,71\)
\(\,\,\,\,\,\,8\times(5-2)^2-1\)
\(\,\,\,\,\,\,8\times(3)^2-1\)
\(\,\,\,\,\,\,8\times9-1\)
\(\,\,\,\,\,\,72-1\)
\(\,\,\,\,\,\,71\)
\(\small{\textbf{19)}}\) \(9\div3+12\div2^2\) The answer is \(6\)
\(\,\,\,\,\,\,9\div3+12\div2^2\)
\(\,\,\,\,\,\,9\div3+12\div4\)
\(\,\,\,\,\,\,3+12\div4\)
\(\,\,\,\,\,\,3+3\)
\(\,\,\,\,\,\,6\)
\(\,\,\,\,\,\,9\div3+12\div2^2\)
\(\,\,\,\,\,\,9\div3+12\div4\)
\(\,\,\,\,\,\,3+12\div4\)
\(\,\,\,\,\,\,3+3\)
\(\,\,\,\,\,\,6\)
\(\small{\textbf{20)}}\) \(8+30\div6\times5\) The answer is \(33\)
\(\,\,\,\,\,\,8+30\div6\times5\)
\(\,\,\,\,\,\,8+5\times5\)
\(\,\,\,\,\,\,8+25\)
\(\,\,\,\,\,\,33\)
\(\,\,\,\,\,\,8+30\div6\times5\)
\(\,\,\,\,\,\,8+5\times5\)
\(\,\,\,\,\,\,8+25\)
\(\,\,\,\,\,\,33\)
\(\small{\textbf{21)}}\) \(24 \div (2 \times 4)\) The answer is \(3\)
\(\,\,\,\,\,\,24 \div (2 \times 4)\)
\(\,\,\,\,\,\,24 \div (8)\)
\(\,\,\,\,\,\,3\)
\(\,\,\,\,\,\,24 \div (2 \times 4)\)
\(\,\,\,\,\,\,24 \div (8)\)
\(\,\,\,\,\,\,3\)
\(\small{\textbf{22)}}\) \((6-4)\times(3\times2)\) The answer is \(12\)
\(\,\,\,\,\,\,(6-4)\times(3\times2)\)
\(\,\,\,\,\,\,(2)\times(3\times2)\)
\(\,\,\,\,\,\,(2)\times(6)\)
\(\,\,\,\,\,\,12\)
\(\,\,\,\,\,\,(6-4)\times(3\times2)\)
\(\,\,\,\,\,\,(2)\times(3\times2)\)
\(\,\,\,\,\,\,(2)\times(6)\)
\(\,\,\,\,\,\,12\)
\(\small{\textbf{23)}}\) \(2^2+3 \times 2\) The answer is \(10\)
\(\,\,\,\,\,\,2^2+3 \times 2\)
\(\,\,\,\,\,\,4+3 \times 2\)
\(\,\,\,\,\,\,4+6\)
\(\,\,\,\,\,\,10\)
\(\,\,\,\,\,\,2^2+3 \times 2\)
\(\,\,\,\,\,\,4+3 \times 2\)
\(\,\,\,\,\,\,4+6\)
\(\,\,\,\,\,\,10\)
\(\small{\textbf{24)}}\) \(8\div 2+2\) The answer is \(6\)
\(\,\,\,\,\,\,8\div 2+2\)
\(\,\,\,\,\,\,4+2\)
\(\,\,\,\,\,\,6\)
\(\,\,\,\,\,\,8\div 2+2\)
\(\,\,\,\,\,\,4+2\)
\(\,\,\,\,\,\,6\)
