Problems & Videos
Solve for x.
\(\textbf{1)}\) \( \sqrt{3x+1}-4=0 \)
The answer is \( x=5 \)
\(\textbf{2)}\) \( 3\sqrt{x+1}=12 \)
The answer is \( x=15 \)
\(\textbf{3)}\) \( \sqrt{x+1}+\sqrt{x-6}=7 \)
The answer is \( x=15 \)
\(\textbf{4)}\) \( \sqrt{x+1}=\sqrt{2x-7} \)
The answer is \( x=8 \)
\(\textbf{5)}\) \( \sqrt[3]{x+1}=2 \)
The answer is \( x=7 \)
\(\textbf{6)}\) \( (x-5)^{(3/2)}=27 \)
The answer is \( x=14 \)
\(\textbf{7)}\) \( \sqrt{x+1}=-5 \)
The answer is No solution
\(\textbf{8)}\) \( \sqrt{x+5}=\sqrt{x}+1 \)
The answer is \( x=4\)
.
\(\,\,\,\,\,\sqrt{x+5}=\sqrt{x}+1\)
\(\,\,\,\,\,\left(\sqrt{x+5}\right)^2=\left(\sqrt{x}+1\right)^2\)
\(\,\,\,\,\,x+5=\left(\sqrt{x}+1\right)\left(\sqrt{x}+1\right)\)
\(\,\,\,\,\,x+5=x+2\sqrt{x}+1\)
\(\,\,\,\,\,4=2\sqrt{x}\)
\(\,\,\,\,\,2=\sqrt{x}\)
\(\,\,\,\,\,2^2=\left(\sqrt{x}\right)^2\)
\(\,\,\,\,\,4=x\)
The answer is \( x=4\)
\(\textbf{9)}\) \(10-\sqrt{y}=\frac{4}{5}\sqrt{y}+1\)
The answer is \( y=25\)
\(\textbf{10)}\) \(\sqrt{x-5}=5-\sqrt{x}\)
The answer is \( x=9\)
\(\textbf{11)}\) \(\sqrt{x-1}=1-\sqrt{x}\)
The answer is \( x=1\)
\(\textbf{12)}\) \(x=\sqrt{x+2}\)
The answer is \( x=2\)
Notes
See Related Pages\(\)
