Practice Problems
Find the equation of the slant (or oblique) asymptote.
\(\textbf{1)}\) \(y=\displaystyle\frac{x^3+4x-5}{x^2+3x}\)
The slant asymptote is \(y=x-3\)
\(\textbf{2)}\) \(y=\displaystyle\frac{x^2+9x+2}{x+4}\)
The slant asymptote is \(y=x+5\)
\(\textbf{3)}\) \(y=\displaystyle\frac{3x^2+14x+2}{x+4}\)
The slant asymptote is \(y=3x+2\)
\(\textbf{4)}\) \(y=\displaystyle-\frac{2x^2-15x+2}{2x-3}\)
The slant asymptote is \(y=-x+6\)
\(\textbf{5)}\) \(y=\displaystyle\frac{4x^3+5x^2-2x+3}{x^2+4}\)
The slant asymptote is \(y=4x+5\)
See Related Pages\(\)
