Questions & Solutions
\(\textbf{1)}\) \(4x+6+2x+1=37\)
\(\textbf{2)}\) \(5x+4+5x+7=1\)
\(\textbf{3)}\) \(3x+2+x+12=30\)
\(\textbf{4)}\) \(3x+5-2x+8=20\)
\(\textbf{5)}\) \(14x+6-12-8x=18\)
\(\textbf{6)}\) \(3x+6+5x-25=x+2\)
\(\textbf{7)}\) \(4x-12-2x+16=5x+4\)
