Notes

Problems and Videos
For numbers \(1-2\), find the center, the radius and graph the circles
\(\textbf{1)}\) \(x^2+y^2=16\) The answer is center \((0,0) \,\,\), radius \(4\)


\(\textbf{2)}\) \((x-3)^2+(y+4)^2=25\) The answer is center \((3,-4) \,\,\), radius \(5\)


For numbers \(3-7\), find the equation of the circle
\(\textbf{3)}\) Equation of a circle with endpoints \((4,5)\) and \((-2,-3)\).
The equation is \((x-1)^2+(y-1)^2=25\)
\(\textbf{4)}\) Equation of a circle with center \((2,8)\) and tangent to the x axis.
The equation is \((x-2)^2+(y-8)^2=64\)
\(\textbf{5)}\) Equation of a circle with center \((-5,3)\) and point on the circle \((7,-2)\).
The equation is \((x+5)^2+(y-3)^2=169\)
\(\textbf{6)}\) Equation of a circle with center \((1/2,7)\) and radius \(\sqrt{5}\).
The equation is \((x-\frac{1}{2})^2+(y-7)^2=5\)
\(\textbf{7)}\) Write the equation of the circle graphed below.

The equation is \((x+2)^2+(y-4)^2=9\)
\(\textbf{8)}\) Use completing the square to find the center and radius of this circle. \(x^2+8x+y^2-6y=11\).
The equation is \((x+4)^2+(y-3)^2=36,\,\,\)
The center is \((-4,3),\,\,\)
The radius is \(6\)
\(\textbf{9)}\) Use completing the square to find the center and radius of this circle. \(x^2+y^2+2x-8y-19=0\).
The equation is \((x+1)^2+(y-4)^2=36,\,\,\)
The Center is \((-1,4),\,\,\)
The Radius is \(6\)
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