The eccentricity of a conic section is a measure of how much the shape deviates from a circle.
If two conic sections have the same eccentricity, then they are similar.
Notes
\(\text{Eccentricity}=\displaystyle\frac{\text{Distance from Center to Focus (c)}}{\text{Distance from Center to Vertex (a)}}\)
| \({\text{Conic Sections & Eccentricity}}\) |
| \(\underline{\text{Conic Section}}\) |
\(\underline{\text{Eccentricity (e)}}\) |
| \(\text{Circle}\) |
\(e=0\) |
| \(\text{Ellipse}\) |
\(0 \lt e \lt 1\) |
| \(\text{Parabola}\) |
\(e=1\) |
| \(\text{Hyperbola}\) |
\(e \gt 1\) |
| \({\text{Ellipses}}\) |
| \(\text{Equation}\) |
\(\displaystyle\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\)
\(a\gt b\) |
\(\displaystyle\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1\)
\(a\gt b\) |
| \(\text{Shape}\) |
 |
 |
| \(\text{Foci}\) |
\((h \pm c,k)\) |
\((h ,k \pm c)\) |
| \(\text{Vertices}\) |
\((h \pm a,k)\) |
\((h ,k \pm a)\) |
| \(\text{Center}\) |
\((h,k)\) |
| \(\text{Focal Length Equation}\) |
\(a^2-b^2=c^2\) |
| \(\text{Length of Major Axis}\) |
\(2a\) |
| \(\text{Length of Minor Axis}\) |
\(2b\) |
| \(\text{Eccentricity}\) |
\(\displaystyle\frac{c}{a}\) |

Practice Problems
\(\textbf{1)}\) Find the eccentricity of the following circle.
\(\displaystyle(x-4)^2+y^2=16\)
The eccentricity is \( e=0 \)
All Circles have eccentricity \( e=0 \)
\(\textbf{2)}\) Find the eccentricity of the following ellipse.
\(\displaystyle\frac{x^2}{16}+\displaystyle\frac{y^2}{25}=1\)
\(\,\,\,\)The eccentricity is \( e=\displaystyle\frac{3}{5} \)
\(\,\,\,\text{For ellipses, } a^2-b^2=c^2\)
\(\,\,\, 25-16=c^2\)
\(\,\,\, 9=c^2\)
\(\,\,\, c=3\)
\(\,\,\, e=\displaystyle \frac{c}{a}\)
\(\,\,\, e=\displaystyle \frac{3}{5}\)
\(\textbf{3)}\) Find the eccentricity of the following parabola.
\(\displaystyle y= 4(x+2)^2+3\)
The eccentricity is \( e=1 \)
All Parabolas have eccentricity \( e=1 \)
\(\textbf{4)}\) Find the eccentricity of the following hyperbola.
\(\displaystyle\frac{x^2}{144}-\displaystyle\frac{y^2}{25}=1\)
\(\,\,\,\)The eccentricity is \( e=\displaystyle\frac{13}{12} \)
\(\,\,\,\text{For hyperbolas, } a^2+b^2=c^2\)
\(\,\,\, 144+25=c^2\)
\(\,\,\, 169=c^2\)
\(\,\,\, c=13\)
\(\,\,\, e=\displaystyle \frac{c}{a}\)
\(\,\,\, e=\displaystyle \frac{13}{12}\)
Challenge Problem
\(\textbf{5)}\) Find the equation of the ellipse with vertices at (-10, 0) and (10, 0) with an eccentricity of \(\frac{3}{5}\).
\(\,\,\,\)The equation is \(\displaystyle\frac{x^2}{100}+\frac{y^2}{64}=1 \)
\(\,\,\,\left(\text{Center is Midpoint of Vertices}\right)\,\,\, \displaystyle\left(\frac{-10+10}{2},\frac{0-0}{2}\right)=\left(0,0\right)\)
\(\,\,\,\left(a= \text{Distance from Center to a Vertex}\right)\,\,\, a=10\)
\(\,\,\,\left(\text{Eccentricity Formula}\right)\,\,\, \displaystyle e=\frac{c}{a}\)
\(\,\,\,\left(\text{Fill in } e \text{ and } a\right),\,\,\, \displaystyle \frac{3}{5}=\frac{c}{10}\)
\(\,\,\,\left(\text{Cross Multiply}\right)\,\,\, \displaystyle 30=5c\)
\(\,\,\, c=6\)
\(\,\,\,\left(\text{For ellipses}\right)\,\,\, a^2-b^2=c^2\)
\(\,\,\, 100-b^2=36\)
\(\,\,\, b^2=64\)
\(\,\,\, b=8\)
\(\,\,\,\left(\text{Equation Horizontal Ellipses}\right)\,\,\, \displaystyle\frac{\left(x-h\right)^2}{a^2}+\frac{\left(y-k\right)^2}{b^2}=1\)
\(\,\,\,\left(\text{Fill in what we know.}\right)\,\,\, \displaystyle\frac{(x-0)^2}{100}+\frac{(y-0)^2}{64}=1\)
\(\,\,\,\left(\text{Clean it up}\right) \displaystyle\frac{x^2}{100}+\frac{y^2}{64}=1\)
See Related Pages\(\)
