Notes

Questions
Find the infinite geometric series
\(\textbf{1)}\) \(a_1=8 \,\, r=.75 \)
The answer is \(32\)
\(\,\,\,\,\,\,S_\infty=\frac{a_1}{1-r},\,\,\,|r|\lt 1\)
\(\,\,\,\,\,\,|.75|\lt 1\)
\(\,\,\,\,\,\,S_\infty=\frac{8}{1-.75}\)
\(\,\,\,\,\,\,S_\infty=\frac{8}{.25}\)
\(\,\,\,\,\,\,S_\infty=32\)
\(\textbf{2)}\) \(a_1=.75 \,\, r=8 \)
The answer is Divergent
\(\textbf{3)}\) \(\displaystyle\frac{1}{2}+\displaystyle\frac{1}{4}+\displaystyle\frac{1}{8}+\displaystyle\frac{1}{16}+ \cdots\)
The answer is \(1\)
\(\,\,\,\,\,\,S_\infty=\frac{a_1}{1-r},\,\,\,|r|\lt 1\)
\(\,\,\,\,\,\,a_1=\frac{1}{2},\,\,\,r=\frac{1/4}{1/2}=\frac{1}{2} \)
\(\,\,\,\,\,\,|\frac{1}{2}|\lt 1\)
\(\,\,\,\,\,\,S_\infty=\frac{\frac{1}{2}}{1-\frac{1}{2}}\)
\(\,\,\,\,\,\,S_\infty=\frac{\frac{1}{2}}{\frac{1}{2}}\)
\(\,\,\,\,\,\,S_\infty=1\)
\(\textbf{4)}\) \(\displaystyle\frac{1}{2}-\displaystyle\frac{1}{4}+\displaystyle\frac{1}{8}-\displaystyle\frac{1}{16}+ \cdots\)
The answer is \(\displaystyle\frac{1}{3}\)
\(\textbf{5)}\) \(\displaystyle\frac{1}{20}-\displaystyle\frac{1}{10}+\displaystyle\frac{1}{5}-\displaystyle\frac{2}{5}+ \cdots\)
The answer is Divergent
\(\textbf{6)}\) \( \displaystyle \sum_{i=1}^{\infty} 4\left( \frac{1}{3} \right)^{i-1} \)
The answer is \( 6 \)
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