When multiplying complex numbers, you distribute as you normally would when multiplying poloynomials. The major difference is all \(i^2\) need to be replaced with \(-1\) since \(i^2=-1\).
Notes
\(\text{Most Important Note}\)
\(i^2=-1\)
\(\text{Other Notes}\)
\(i=\sqrt{-1}\)
\(i^2=-1\)
\(i^3=-i\)
\(i^4=1\)
\(i^5=i\)
\(i^6=-1\)
\(i^7=-i\)
\(i^8=1\)
Questions & Solutions
\(\textbf{1)}\)Simplify \( (5+i)(5-i) \)
The answer is \( 26 \)
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\(\textbf{2)}\) Simplify \( (3+i)(3-i) \)
The answer is \( 10 \)
\(\,\,\,\,\,\,(3+i)(3-i)\)
\(\,\,\,\,\,\,25-5i+5i-i^2\)
\(\,\,\,\,\,\,9-i^2\)
\(\,\,\,\,\,\,9-(-1)\)
\(\,\,\,\,\,\,9+1\)
\(\,\,\,\,\,\,\)The answer is \( 10 \)
\(\textbf{3)}\) Simplify \( (4+3i)(5-6i) \)
The answer is \( 38-9i \)
\(\textbf{4)}\) Simplify \( (5-2i)(7-i) \)
The answer is \( 33-19i \)
\(\,\,\,\,\,\,(5-2i)(7-i)\)
\(\,\,\,\,\,\,35-5i-14i+2i^2\)
\(\,\,\,\,\,\,35-19i+2(-1)\)
\(\,\,\,\,\,\,35-19i-2\)
\(\,\,\,\,\,\,33-19i\)
\(\,\,\,\,\,\,\)The answer is \( 33-19i \)
\(\textbf{5)}\) Simplify \( i(3+4i) \)
The answer is \( -4+3i \)
\(\,\,\,\,\,\,i(3+4i)\)
\(\,\,\,\,\,\,3i+4i^2\)
\(\,\,\,\,\,\,3i+4(-1)\)
\(\,\,\,\,\,\,3i-4\)
\(\,\,\,\,\,\,\)The answer is \( -4+3i \)
\(\textbf{6)}\) Simplify \( i(2-5i) \)
The answer is \( 5+2i \)
\(\,\,\,\,\,\,i(2-5i)\)
\(\,\,\,\,\,\,2i-5i^2\)
\(\,\,\,\,\,\,2i-5(-1)\)
\(\,\,\,\,\,\,2i+5\)
\(\,\,\,\,\,\,\)The answer is \( 5+2i \)
\(\textbf{7)}\) Simplify \( (5+3i)(5-3i) \)
The answer is \( 34 \)
\(\,\,\,\,\,\,(5+3i)(5-3i)\)
\(\,\,\,\,\,\,25-15i+15i-9i^2\)
\(\,\,\,\,\,\,25-9i^2\)
\(\,\,\,\,\,\,25-9(-1)\)
\(\,\,\,\,\,\,25+9\)
\(\,\,\,\,\,\,\)The answer is \( 34 \)
\(\textbf{8)}\) Simplify \( 3(2+3i) \)
The answer is \( 6+9i \)
\(\,\,\,\,\,\,3(2+3i)\)
\(\,\,\,\,\,\,6+9i\)
\(\,\,\,\,\,\,\)The answer is \( 6+9i \)
Challenge Questions
\(\textbf{9)}\) Simplify \( (a+bi)(a-bi) \)
The answer is \( a^2+b^2 \)
\(\textbf{10)}\) What is \( (1+\sqrt{-1})(1-\sqrt{-1}) ? \)
The answer is \( 2 \)
\(\textbf{11)}\) Simplify \( (5i-2i^7)(7-i^3) \)
The answer is \( -7+49i \)
\( (5i-2i^7)(7-i^3) \)
\( 35i-5i^4-14i^7+2i^{10}\)
\( 35i-5i^4-14i^3+2i^{2}\)
\( 35i-5(1)-14(-i)+2(-1)\)
\( 35i-5+14i-2\)
\( -7+49i \)
\(\textbf{12)}\) Simplify \( (3i^5+4i^7)(6i-2i^6) \)
The answer is \( 6-2i \)
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