Practice Problems
\(\textbf{1)}\) Write the polynomial equation with roots \(4,\) and \(6\) and leading coefficient \(1\).
The answer is \( y=x^2-10x+24 \)
\(\,\,\,\,\,\,\text{when root is }4 \, \Rightarrow \, \text{factor is }(x-4)\)
\(\,\,\,\,\,\,\text{when root is }6 \, \Rightarrow \, \text{factor is }(x-6)\)
\(\,\,\,\,\,\,y=(x-4)(x-6)\)
\(\,\,\,\,\,\,y=x^2-6x-4x+24\)
\(\,\,\,\,\,\,\)The answer is \( y=x^2-10x+24 \)
\(\textbf{2)}\) Write the polynomial equation with roots \(1,\) and \(-3\) and leading coefficient \(1\).
The answer is \( y=x^2+2x-3 \)
\(\,\,\,\,\,\,\text{when root is }1 \, \Rightarrow \, \text{factor is }(x-1)\)
\(\,\,\,\,\,\,\text{when root is }-3 \, \Rightarrow \, \text{factor is }(x+3)\)
\(\,\,\,\,\,\,y=(x-1)(x+3)\)
\(\,\,\,\,\,\,y=x^2-1x+3x-3\)
\(\,\,\,\,\,\,\)The answer is \( y=x^2+2x-3 \)
\(\textbf{3)}\) Write the polynomial equation with roots \(0\) and \(2\) and leading coefficient \(1\).
The answer is \( y=x^2-2x \)
\(\,\,\,\,\,\,\text{when root is }0 \, \Rightarrow \, \text{factor is }(x)\)
\(\,\,\,\,\,\,\text{when root is }2 \, \Rightarrow \, \text{factor is }(x-2)\)
\(\,\,\,\,\,\,y=(x)(x-2)\)
\(\,\,\,\,\,\,y=x^2-2x\)
\(\,\,\,\,\,\,\)The answer is \( y=x^2-2x \)
\(\textbf{4)}\) Write the polynomial equation with roots \(-3,\) and \(2,\) and \(-7\) and leading coefficient \(1\).
The answer is \( y=x^3+8x^2+x-42 \)
\(\,\,\,\,\,\,\text{when root is }-3 \, \Rightarrow \, \text{factor is }(x+3)\)
\(\,\,\,\,\,\,\text{when root is }2 \, \Rightarrow \, \text{factor is }(x-2)\)
\(\,\,\,\,\,\,\text{when root is }-7 \, \Rightarrow \, \text{factor is }(x+7)\)
\(\,\,\,\,\,\,y=(x+3)(x-2)(x+7)\)
\(\,\,\,\,\,\,y=\left[(x+3)(x-2)\right](x+7)\)
\(\,\,\,\,\,\,y=\left[x^2+3x-2x-6\right](x+7)\)
\(\,\,\,\,\,\,y=\left[x^2+x-6\right](x+7)\)
\(\,\,\,\,\,\,y=x^3+x^2-6x+7x^2+7x-42\)
\(\,\,\,\,\,\,\)The answer is \( y=x^3+8x^2+x-42 \)
\(\textbf{5)}\) Write the polynomial equation with roots \(4,\) and \(3i,\) and leading coefficient \(1\).
The answer is \( y=x^3-4x^2+9x-36 \)
\(\,\,\,\,\,\,\text{when root is }4 \, \Rightarrow \, \text{factor is }(x-4)\)
\(\,\,\,\,\,\,\text{when root is }3i \, \Rightarrow \, \text{factor is }(x-3i)\)
\(\,\,\,\,\,\,\text{when root is }-3i \, \Rightarrow \, \text{factor is }(x+3i)\)
\(\,\,\,\,\,\,y=(x-4)(x-3i)(x+3i)\)
\(\,\,\,\,\,\,y=(x-4)(x^2+9)\)
\(\,\,\,\,\,\,y=x^3-4x^2+9x-36\)
\(\,\,\,\,\,\,\)The answer is \( y=x^3-4x^2+9x-36 \)
\(\textbf{6)}\) Write the polynomial equation with roots \(-2,\) and \(5+i,\) and leading coefficient \(1\).
The answer is \( y=x^3-8x^2+6x+52 \)
\(\,\,\,\,\,\,\text{when root is }-2 \, \Rightarrow \, \text{factor is }(x+2)\)
\(\,\,\,\,\,\,\text{when root is }5+i \, \Rightarrow \, \text{factor is }(x-5-i)\)
\(\,\,\,\,\,\,\text{when root is }5-i \, \Rightarrow \, \text{factor is }(x-5+i)\)
\(\,\,\,\,\,\,y=(x+2)(x-5-i)(x-5+i)\)
\(\,\,\,\,\,\,y=(x+2)(x^2-10x+26)\)
\(\,\,\,\,\,\,y=x^3-8x^2+6x+52\)
\(\,\,\,\,\,\,\)The answer is \( y=x^3-8x^2+6x+52 \)
See Related Pages\(\)