The “Co” in Cofunction identities is short for complementary. It shows the relationship between sine & cosine, tangent & cotangent, and secant & cosecant. A particular angle’s trig function is equal to the the angle’s complement’s cofunction. Note that \(\frac{\pi}{2}\) radians \(= 90^{\circ}\)
Notes
Cofunction Identities (Radians)
\(\sin{(x)} = \cos{\left(\frac{\pi}{2} -x\right)}\)
\(\cos{(x)} = \sin{\left(\frac{\pi}{2} -x\right)}\)
\(\sec{(x)} = \csc{\left(\frac{\pi}{2} -x\right)}\)
\(\csc{(x)} = \sec{\left(\frac{\pi}{2} -x\right)}\)
\(\tan{(x)} = \cot{\left(\frac{\pi}{2} -x\right)}\)
\(\cot{(x)} = \tan{\left(\frac{\pi}{2} -x\right)}\)
Cofunction Identities (Degrees)
\(\sin{(\theta)} = \cos{\left(90 -\theta\right)}\)
\(\cos{(\theta)} = \sin{\left(90 -\theta\right)}\)
\(\sec{(\theta)} = \csc{\left(90 -\theta\right)}\)
\(\csc{(\theta)} = \sec{\left(90 -\theta\right)}\)
\(\tan{(\theta)} = \cot{\left(90 -\theta\right)}\)
\(\cot{(\theta)} = \tan{\left(90 -\theta\right)}\)
Practice Problems
\(\textbf{1)}\) Solve for x using the cofunction identities
\( \sin{\frac{\pi}{6}}=\cos{x} \)
\(\textbf{2)}\) Solve for x using the cofunction identities
\( \csc{\frac{2\pi}{5}}=\sec{x} \)
\(\textbf{3)}\) Solve for x using the cofunction identities
\( \tan{\frac{\pi}{5}}=\cot{x} \)
\(\textbf{4)}\) Solve for x using the cofunction identities
\( \cos{\frac{8\pi}{9}}=\sin{x} \)
\(\textbf{5)}\) Simplify \( \displaystyle \frac{\tan^{2}}{\csc\left(\frac{\pi}{2}-x\right)+1} \)

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