Cofunction identities show that a trig function of an angle is equal to its cofunction of the complementary angle. The “Co” in cofunction means complementary, connecting sine with cosine, tangent with cotangent, and secant with cosecant. In degrees, complementary angles add to \(90^\circ\), and in radians they add to \(\frac{\pi}{2}\). These identities are useful for solving missing-angle problems and simplifying expressions involving cofunction pairs.
Notes
Cofunction Identities (Radians)
\(\sin{(x)} = \cos{\left(\frac{\pi}{2} -x\right)}\)
\(\cos{(x)} = \sin{\left(\frac{\pi}{2} -x\right)}\)
\(\sec{(x)} = \csc{\left(\frac{\pi}{2} -x\right)}\)
\(\csc{(x)} = \sec{\left(\frac{\pi}{2} -x\right)}\)
\(\tan{(x)} = \cot{\left(\frac{\pi}{2} -x\right)}\)
\(\cot{(x)} = \tan{\left(\frac{\pi}{2} -x\right)}\)
Cofunction Identities (Degrees)
\(\sin{(\theta)} = \cos{\left(90 -\theta\right)}\)
\(\cos{(\theta)} = \sin{\left(90 -\theta\right)}\)
\(\sec{(\theta)} = \csc{\left(90 -\theta\right)}\)
\(\csc{(\theta)} = \sec{\left(90 -\theta\right)}\)
\(\tan{(\theta)} = \cot{\left(90 -\theta\right)}\)
\(\cot{(\theta)} = \tan{\left(90 -\theta\right)}\)
Practice Problems
\(\textbf{1)}\) Solve for x using the cofunction identities
\( \sin{\frac{\pi}{6}}=\cos{x} \)
The answer is \( x=\frac{\pi}{3} \)
\(\sin{\left(\frac{\pi}{6}\right)}=\cos{x}\)
\(\sin{\theta}=\cos{\left(\frac{\pi}{2}-\theta\right)}\)
\(\sin{\left(\frac{\pi}{6}\right)}=\cos{\left(\frac{\pi}{2}-\frac{\pi}{6}\right)}\)
\(\sin{\left(\frac{\pi}{6}\right)}=\cos{\left(\frac{3\pi}{6}-\frac{\pi}{6}\right)}\)
\(\sin{\left(\frac{\pi}{6}\right)}=\cos{\left(\frac{\pi}{3}\right)}\)
\(x=\frac{\pi}{3}\)
\(\textbf{2)}\) Solve for x using the cofunction identities
\( \csc{\frac{2\pi}{5}}=\sec{x} \)
The answer is \( x=\frac{\pi}{10} \)
\(\csc{\left(\frac{2\pi}{5}\right)}=\sec{x}\)
\(\csc{\theta}=\sec{\left(\frac{\pi}{2}-\theta\right)}\)
\(\csc{\left(\frac{2\pi}{5}\right)}=\sec{\left(\frac{\pi}{2}-\frac{2\pi}{5}\right)}\)
\(\csc{\left(\frac{2\pi}{5}\right)}=\sec{\left(\frac{5\pi}{10}-\frac{4\pi}{10}\right)}\)
\(\csc{\left(\frac{2\pi}{5}\right)}=\sec{\left(\frac{\pi}{10}\right)}\)
\(x=\frac{\pi}{10}\)
\(\textbf{3)}\) Solve for x using the cofunction identities
\( \tan{\frac{\pi}{5}}=\cot{x} \)
The answer is \( x=\frac{3\pi}{10} \)
\(\tan{\left(\frac{\pi}{5}\right)}=\cot{x}\)
\(\tan{\theta}=\cot{\left(\frac{\pi}{2}-\theta\right)}\)
\(\tan{\left(\frac{\pi}{5}\right)}=\cot{\left(\frac{\pi}{2}-\frac{\pi}{5}\right)}\)
\(\tan{\left(\frac{\pi}{5}\right)}=\cot{\left(\frac{5\pi}{10}-\frac{2\pi}{10}\right)}\)
\(\tan{\left(\frac{\pi}{5}\right)}=\cot{\left(\frac{3\pi}{10}\right)}\)
\(x=\frac{3\pi}{10}\)
\(\textbf{4)}\) Solve for x using the cofunction identities
\( \cos{\frac{8\pi}{9}}=\sin{x} \)
The answer is \( x=-\frac{7\pi}{18} \)
\(\cos{\left(\frac{8\pi}{9}\right)}=\sin{x}\)
\(\cos{\theta}=\sin{\left(\frac{\pi}{2}-\theta\right)}\)
\(\cos{\left(\frac{8\pi}{9}\right)}=\sin{\left(\frac{\pi}{2}-\frac{8\pi}{9}\right)}\)
\(\cos{\left(\frac{8\pi}{9}\right)}=\sin{\left(\frac{9\pi}{18}-\frac{16\pi}{18}\right)}\)
\(\cos{\left(\frac{8\pi}{9}\right)}=\sin{\left(-\frac{7\pi}{18}\right)}\)
\(x=-\frac{7\pi}{18}\)
\(\textbf{5)}\) Simplify \(\csc{\left(90^\circ-x\right)}\)
The answer is \(\sec{x}\)
\(\csc{\left(90^\circ-x\right)}\)
\(\csc{\left(90^\circ-x\right)}=\sec{x}\)
\(\text{The cosecant of a complementary angle equals secant.}\)
\(\text{The answer is }\sec{x}\)
\(\textbf{6)}\) Solve for x using the cofunction identities
\(\cos{35^\circ}=\sin{x}\)
The answer is \(x=55^\circ\)
\(\cos{35^\circ}=\sin{x}\)
\(\cos{\theta}=\sin{(90^\circ-\theta)}\)
\(\cos{35^\circ}=\sin{(90^\circ-35^\circ)}\)
\(\cos{35^\circ}=\sin{55^\circ}\)
\(x=55^\circ\)
\(\textbf{7)}\) Solve for x using the cofunction identities
\(\tan{22^\circ}=\cot{x}\)
The answer is \(x=68^\circ\)
\(\tan{22^\circ}=\cot{x}\)
\(\tan{\theta}=\cot{(90^\circ-\theta)}\)
\(\tan{22^\circ}=\cot{(90^\circ-22^\circ)}\)
\(\tan{22^\circ}=\cot{68^\circ}\)
\(x=68^\circ\)
\(\textbf{8)}\) Solve for x using the cofunction identities
\(\sec{70^\circ}=\csc{x}\)
The answer is \(x=20^\circ\)
\(\sec{70^\circ}=\csc{x}\)
\(\sec{\theta}=\csc{(90^\circ-\theta)}\)
\(\sec{70^\circ}=\csc{(90^\circ-70^\circ)}\)
\(\sec{70^\circ}=\csc{20^\circ}\)
\(x=20^\circ\)
\(\textbf{9)}\) Solve for x using the cofunction identities
\(\sin{42^\circ}=\cos{x}\)
The answer is \(x=48^\circ\)
\(\sin{42^\circ}=\cos{x}\)
\(\sin{\theta}=\cos{(90^\circ-\theta)}\)
\(\sin{42^\circ}=\cos{(90^\circ-42^\circ)}\)
\(\sin{42^\circ}=\cos{48^\circ}\)
\(x=48^\circ\)
\(\textbf{10)}\) Solve for x using the cofunction identities
\(\cot{17^\circ}=\tan{x}\)
The answer is \(x=73^\circ\)
\(\cot{17^\circ}=\tan{x}\)
\(\cot{\theta}=\tan{(90^\circ-\theta)}\)
\(\cot{17^\circ}=\tan{(90^\circ-17^\circ)}\)
\(\cot{17^\circ}=\tan{73^\circ}\)
\(x=73^\circ\)
\(\textbf{11)}\) Solve for x using the cofunction identities
\(\cos{\left(\frac{\pi}{4}\right)}=\sin{x}\)
The answer is \(x=\frac{\pi}{4}\)
\(\cos{\left(\frac{\pi}{4}\right)}=\sin{x}\)
\(\cos{\theta}=\sin{\left(\frac{\pi}{2}-\theta\right)}\)
\(\cos{\left(\frac{\pi}{4}\right)}=\sin{\left(\frac{\pi}{2}-\frac{\pi}{4}\right)}\)
\(\cos{\left(\frac{\pi}{4}\right)}=\sin{\left(\frac{2\pi}{4}-\frac{\pi}{4}\right)}\)
\(\cos{\left(\frac{\pi}{4}\right)}=\sin{\left(\frac{\pi}{4}\right)}\)
\(x=\frac{\pi}{4}\)
\(\textbf{12)}\) Solve for x using the cofunction identities
\(\sec{\left(\frac{5\pi}{12}\right)}=\csc{x}\)
The answer is \(x=\frac{\pi}{12}\)
\(\sec{\left(\frac{5\pi}{12}\right)}=\csc{x}\)
\(\sec{\theta}=\csc{\left(\frac{\pi}{2}-\theta\right)}\)
\(\sec{\left(\frac{5\pi}{12}\right)}=\csc{\left(\frac{\pi}{2}-\frac{5\pi}{12}\right)}\)
\(\sec{\left(\frac{5\pi}{12}\right)}=\csc{\left(\frac{6\pi}{12}-\frac{5\pi}{12}\right)}\)
\(\sec{\left(\frac{5\pi}{12}\right)}=\csc{\left(\frac{\pi}{12}\right)}\)
\(x=\frac{\pi}{12}\)
\(\textbf{13)}\) Solve for x using the cofunction identities
\(\cot{\left(\frac{7\pi}{18}\right)}=\tan{x}\)
The answer is \(x=\frac{\pi}{9}\)
\(\cot{\left(\frac{7\pi}{18}\right)}=\tan{x}\)
\(\cot{\theta}=\tan{\left(\frac{\pi}{2}-\theta\right)}\)
\(\cot{\left(\frac{7\pi}{18}\right)}=\tan{\left(\frac{\pi}{2}-\frac{7\pi}{18}\right)}\)
\(\cot{\left(\frac{7\pi}{18}\right)}=\tan{\left(\frac{9\pi}{18}-\frac{7\pi}{18}\right)}\)
\(\cot{\left(\frac{7\pi}{18}\right)}=\tan{\left(\frac{2\pi}{18}\right)}\)
\(x=\frac{\pi}{9}\)
\(\textbf{14)}\) Solve for x using the cofunction identities
\(\csc{\left(\frac{\pi}{9}\right)}=\sec{x}\)
The answer is \(x=\frac{7\pi}{18}\)
\(\csc{\left(\frac{\pi}{9}\right)}=\sec{x}\)
\(\csc{\theta}=\sec{\left(\frac{\pi}{2}-\theta\right)}\)
\(\csc{\left(\frac{\pi}{9}\right)}=\sec{\left(\frac{\pi}{2}-\frac{\pi}{9}\right)}\)
\(\csc{\left(\frac{\pi}{9}\right)}=\sec{\left(\frac{9\pi}{18}-\frac{2\pi}{18}\right)}\)
\(\csc{\left(\frac{\pi}{9}\right)}=\sec{\left(\frac{7\pi}{18}\right)}\)
\(x=\frac{7\pi}{18}\)
\(\textbf{15)}\) Simplify \(\sin{\left(\frac{\pi}{2}-x\right)}\)
The answer is \(\cos{x}\)
\(\sin{\left(\frac{\pi}{2}-x\right)}\)
\(\sin{\left(\frac{\pi}{2}-x\right)}=\cos{x}\)
\(\text{The sine of a complementary angle equals cosine.}\)
\(\text{The answer is }\cos{x}\)
\(\textbf{16)}\) Simplify \(\tan{\left(\frac{\pi}{2}-x\right)}\)
The answer is \(\cot{x}\)
\(\tan{\left(\frac{\pi}{2}-x\right)}\)
\(\tan{\left(\frac{\pi}{2}-x\right)}=\cot{x}\)
\(\text{The tangent of a complementary angle equals cotangent.}\)
\(\text{The answer is }\cot{x}\)
\(\textbf{17)}\) Simplify \(\sec{\left(\frac{\pi}{2}-x\right)}\)
The answer is \(\csc{x}\)
\(\sec{\left(\frac{\pi}{2}-x\right)}\)
\(\sec{\left(\frac{\pi}{2}-x\right)}=\csc{x}\)
\(\text{The secant of a complementary angle equals cosecant.}\)
\(\text{The answer is }\csc{x}\)
\(\textbf{18)}\) Simplify \( \displaystyle \frac{\tan^{2}{x}}{\csc\left(\frac{\pi}{2}-x\right)+1} \)
The answer is \( \sec{x}-1 \)
\(\displaystyle \frac{\tan^{2}{x}}{\csc\left(\frac{\pi}{2}-x\right)+1}\)
\(\displaystyle \frac{\tan^{2}{x}}{\sec{x}+1}\,\,\,\,\,\left(\csc\left(\frac{\pi}{2}-x\right)=\sec{x}\right)\)
\(\displaystyle \frac{\sec^2{x}-1}{\sec{x}+1}\,\,\,\,\,\left(\tan^2{x}=\sec^2{x}-1\right)\)
\(\displaystyle \frac{(\sec{x}-1)(\sec{x}+1)}{\sec{x}+1}\)
\(\sec{x}-1\)
\(\textbf{19)}\) Simplify \(\displaystyle \frac{\cot{x}}{\tan\left(\frac{\pi}{2}-x\right)}\)
The answer is \(1\)
\(\displaystyle \frac{\cot{x}}{\tan\left(\frac{\pi}{2}-x\right)}\)
\(\displaystyle \frac{\cot{x}}{\cot{x}}\,\,\,\,\,\left(\tan\left(\frac{\pi}{2}-x\right)=\cot{x}\right)\)
\(1\)
\(\textbf{20)}\) Simplify \(\displaystyle \frac{\sec{x}}{\csc\left(\frac{\pi}{2}-x\right)}\)
The answer is \(1\)
\(\displaystyle \frac{\sec{x}}{\csc\left(\frac{\pi}{2}-x\right)}\)
\(\displaystyle \frac{\sec{x}}{\sec{x}}\,\,\,\,\,\left(\csc\left(\frac{\pi}{2}-x\right)=\sec{x}\right)\)
\(1\)
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